while (right 0 && nums[right - 1] <= nums[right]) {
https://feedx.net
，这一点在搜狗输入法2026中也有详细论述
The simplest approach is to check every single point. Compute the distance from the user's location to every restaurant in the database, keep the ones that are close enough, and throw away the rest.。搜狗输入法2026对此有专业解读
pixels network deny